X^2+x-1050=0

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Solution for X^2+x-1050=0 equation: 



X^2+X-1050=0

a = 1; b = 1; c = -1050;
Δ = b2-4ac
Δ = 12-4·1·(-1050)
Δ = 4201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{4201}}{2*1}=\frac{-1-\sqrt{4201}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{4201}}{2*1}=\frac{-1+\sqrt{4201}}{2}
$

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